Operator : adjust oscillators frequency in semitone offsets
Posted: Fri Sep 09, 2005 8:09 pm
I was trying to build a sound that had 3 oscillators tuned in a chord, with different envelope for each oscillator (like tuned echos).
there's no direct way to tune each operator in semitones (like 0, +4, +7) - or I didn't find it. Instead you have to use fine tune, which is expressed in thousands of an octave.
So, how do you convert fine tune setting into semitone ? There must be a formula (using log ...) but I was too lazy to look for it.
Instead, I experimented and build a conversion table.
The way I built the table is the following:
- use 2 operators in parallel, with basic sine preset
- play both operators continuously with same note (like C3)
- transpose operator A by -1 semitone (global transpose param)
- adjust operator A osc A fine setting until the 2 operators are in tune (use beating to fine tune)
- record the value
- repeat with 2, 3, ..., 11 semitones
Here is the table :
semitone / fine
0 ----> 0
1 ----> 60
2 ----> 123
3 ----> 189
4 ----> 260
5 ----> 335
6 ----> 414
7 ----> 498
8 ----> 587
9 ----> 682
10 ----> 782
11 ----> 888
12 ----> 1000
If someone has more precise values or the formula, I'd appreciate the update.
EricP
there's no direct way to tune each operator in semitones (like 0, +4, +7) - or I didn't find it. Instead you have to use fine tune, which is expressed in thousands of an octave.
So, how do you convert fine tune setting into semitone ? There must be a formula (using log ...) but I was too lazy to look for it.
Instead, I experimented and build a conversion table.
The way I built the table is the following:
- use 2 operators in parallel, with basic sine preset
- play both operators continuously with same note (like C3)
- transpose operator A by -1 semitone (global transpose param)
- adjust operator A osc A fine setting until the 2 operators are in tune (use beating to fine tune)
- record the value
- repeat with 2, 3, ..., 11 semitones
Here is the table :
semitone / fine
0 ----> 0
1 ----> 60
2 ----> 123
3 ----> 189
4 ----> 260
5 ----> 335
6 ----> 414
7 ----> 498
8 ----> 587
9 ----> 682
10 ----> 782
11 ----> 888
12 ----> 1000
If someone has more precise values or the formula, I'd appreciate the update.
EricP